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Today, I’d like to share a really cool problem I solved from the Japanese Olympiad in Informatics. This problem is Synchronisation from the 2013 Open Contest.

Here’s a quick summary of the problem: You have $N \leq 10^5$ computers and $N - 1$ connections that form a tree. Initially, all connections are inactive and all computers hold a single unique piece of information. Each time the connection between computers $A$ and $B$ is activated, the computers connected to $A$ and $B$ (including $A$ and $B$) sync up and share information. The states of the connections are changed $M \leq 10^5$ times and you would like to know how many unique pieces of information are stored on each computer at the end.

There are many ways to solve this problem (I know of 4 distinct ways), but I’ll share what I think is the most elegant solution, which relies on more observations and has relatively light implementation.

Let’s solve this problem subtask by subtask, just as we would in an actual competition!

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